What is the integral of \sqrt[3]{x^8} ?

The integral of \sqrt[3]{x^8} is 3/11 x^{11/3}+C

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integral of \sqrt[3]{x^8}

\int 3 x^{8} d x

\frac{3}{11} x^{\frac{11}{3}} + C

Solution steps

\int 3 x^{8} d x

3 x^{8} = x^{\frac{8}{3}},

assuming

x \geq 0

= \int x^{\frac{8}{3}} d x

Apply the Power Rule

: \frac{3}{11} x^{\frac{11}{3}}

= \frac{3}{11} x^{\frac{11}{3}}

Add a constant to the solution

= \frac{3}{11} x^{\frac{11}{3}} + C

\frac{d y}{d x} = 0.3 \cdot y

\int \frac{1}{s ( 4 s ) ^{2} - 9} d s

\frac{\partial}{\partial x} (\frac{3 r + s}{t})

\int \frac{ln ( x )}{x ^{6}} d x

y = sin (x), at x = \frac{π}{4}

What is the integral of \sqrt[3]{x^8} ?
The integral of \sqrt[3]{x^8} is 3/11 x^{11/3}+C