What is the tangent of y=sin(x),\at x= pi/4 ?

The tangent of y=sin(x),\at x= pi/4 is y=(sqrt(2))/2 x+1/(sqrt(2))-pi/(4sqrt(2))

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tangent of y=sin(x),\at x= pi/4

tangent of

y = sin (x), at x = \frac{π}{4}

y = \frac{2}{2} x + \frac{1}{2} - \frac{π}{4 2}

Solution steps

Find the tangent point:

(\frac{π}{4}, \frac{2}{2})

Find the slope of

y = sin (x) : \frac{d y}{d x} = cos (x)

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = \frac{2}{2}

Find the line with slope m=

\frac{2}{2}

and passing through

(\frac{π}{4}, \frac{2}{2}) : y = \frac{2}{2} x + \frac{1}{2} - \frac{π}{4 2}

y = \frac{2}{2} x + \frac{1}{2} - \frac{π}{4 2}

\int \frac{1}{( x + 1 ) ^{2} + 4} d x

\int x^{2} x^{3} + 33 d x

\frac{d y}{d x} + y^{5} x + 2 y = 0

\int \frac{1}{x ^{5} x ^{2} - 1} d x

x^{2} - 3 x

What is the tangent of y=sin(x),\at x= pi/4 ?
The tangent of y=sin(x),\at x= pi/4 is y=(sqrt(2))/2 x+1/(sqrt(2))-pi/(4sqrt(2))