What is the solution for (du)/(1+sin(u))=dx ?

The solution for (du)/(1+sin(u))=dx is u(x)=2arctan((-2-x-c_{1})/(x+c_{1)})+2pin

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(du)/(1+sin(u))=dx

\frac{d u}{1 + sin ( u )} = d x

u (x) = 2 arctan (\frac{- 2 - x - c _{1}}{x + c _{1}}) + 2 πn

Solution steps

\frac{d u ( x )}{1 + sin ( u ( x ) )} = d x

Solve separable ODE:

u (x) = 2 arctan (\frac{- 2 - x - c _{1}}{x + c _{1}}) + 2 πn

u (x) = 2 arctan (\frac{- 2 - x - c _{1}}{x + c _{1}}) + 2 πn

5 t \cdot \frac{d y}{d t} - 5 y = t

f (x) = x^{x^{2}}

f (x) = 9 x + 4, (5, 7)

\frac{\partial}{\partial v} (\frac{v - u}{2})

x \to + 0 lim (x^{2} \cdot ln (x))

What is the solution for (du)/(1+sin(u))=dx ?
The solution for (du)/(1+sin(u))=dx is u(x)=2arctan((-2-x-c_{1})/(x+c_{1)})+2pin