What is the first derivative of x^2-3 ?

The first derivative of x^2-3 is 2x

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derivative of x^2-3

derivative of

x^{2} - 3

2 x

Solution steps

\frac{d}{d x} (x^{2} - 3)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) - \frac{d}{d x} (3)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (3) = 0

= 2 x - 0

Simplify

= 2 x

\int (x^{\frac{3}{2}} + 4 x + 3) d x

5 t + 6 t^{5}

\frac{d}{d x} (x (1 - x))

y^{^{'}} + 2 y = 0

x \to \infty lim (7 + \frac{6}{x})