What is the integral of (x+7)/(x^2+4) ?

The integral of (x+7)/(x^2+4) is 1/2 ln|x^2+4|+7/2 arctan(x/2)+C

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integral of (x+7)/(x^2+4)

\int \frac{x + 7}{x ^{2} + 4} d x

\frac{1}{2} ln x^{2} + 4 + \frac{7}{2} arctan (\frac{x}{2}) + C

Solution steps

\int \frac{x + 7}{x ^{2} + 4} d x

Expand

\frac{x + 7}{x ^{2} + 4} : \frac{x}{x ^{2} + 4} + \frac{7}{x ^{2} + 4}

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int \frac{x}{x ^{2} + 4} d x + \int \frac{7}{x ^{2} + 4} d x

\int \frac{x}{x ^{2} + 4} d x = \frac{1}{2} ln x^{2} + 4

\int \frac{7}{x ^{2} + 4} d x = \frac{7}{2} arctan (\frac{x}{2})

= \frac{1}{2} ln x^{2} + 4 + \frac{7}{2} arctan (\frac{x}{2})

Add a constant to the solution

= \frac{1}{2} ln x^{2} + 4 + \frac{7}{2} arctan (\frac{x}{2}) + C

\frac{\partial}{\partial t} (s t u^{2})

7 t \frac{d y}{d t} + y = t^{3}

\frac{d}{d x} (\frac{x}{x + 8})

\int \frac{ln ( x )}{x 1 + ln ( x ^{2} )} d x

y = ln (x x^{2} - 1)

What is the integral of (x+7)/(x^2+4) ?
The integral of (x+7)/(x^2+4) is 1/2 ln|x^2+4|+7/2 arctan(x/2)+C