What is the derivative of 2/t-4/(t^2) ?

The derivative of 2/t-4/(t^2) is -2/(t^2)+8/(t^3)

What is the first derivative of 2/t-4/(t^2) ?

The first derivative of 2/t-4/(t^2) is -2/(t^2)+8/(t^3)

Popular >

derivative of

\frac{2}{t} - \frac{4}{t ^{2}}

- \frac{2}{t ^{2}} + \frac{8}{t ^{3}}

Solution steps

\frac{d}{d t} (\frac{2}{t} - \frac{4}{t ^{2}})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d t} (\frac{2}{t}) - \frac{d}{d t} (\frac{4}{t ^{2}})

\frac{d}{d t} (\frac{2}{t}) = - \frac{2}{t ^{2}}

\frac{d}{d t} (\frac{4}{t ^{2}}) = - \frac{8}{t ^{3}}

= - \frac{2}{t ^{2}} - (- \frac{8}{t ^{3}})

Simplify

= - \frac{2}{t ^{2}} + \frac{8}{t ^{3}}

\int 2 x^{2} - 4 x d x

\int_{0}^{5} 40 e^{- 0.3 t} d t

y^{^{'}} = 7 x e^{y}, y (0) = 0

x \to 0 lim (\frac{a ^{x} - 1}{2 x})

x \to - \infty lim (4 x^{3})

What is the derivative of 2/t-4/(t^2) ?
The derivative of 2/t-4/(t^2) is -2/(t^2)+8/(t^3)
What is the first derivative of 2/t-4/(t^2) ?
The first derivative of 2/t-4/(t^2) is -2/(t^2)+8/(t^3)