What is partialfraction (x^2)/(x^2-1) ?

The solution to partialfraction (x^2)/(x^2-1) is 1-1/(2(x+1))+1/(2(x-1))

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partialfraction (x^2)/(x^2-1)

partial fractions

\frac{x ^{2}}{x ^{2} - 1}

1 - \frac{1}{2 ( x + 1 )} + \frac{1}{2 ( x - 1 )}

Solution steps

\frac{x ^{2}}{x ^{2} - 1}

Long division

\frac{x ^{2}}{x ^{2} - 1} : 1 + \frac{1}{x ^{2} - 1}

= 1 + \frac{1}{x ^{2} - 1}

Continue partial fractions on remainder:

\frac{1}{x ^{2} - 1}

Take the partial fraction of

\frac{1}{x ^{2} - 1} : - \frac{1}{2 ( x + 1 )} + \frac{1}{2 ( x - 1 )}

1 - \frac{1}{2 ( x + 1 )} + \frac{1}{2 ( x - 1 )}

\frac{99 x ^{\frac{7}{2}}}{4}

\int \frac{2 x + 6}{( ( x + 1 ) ^{2} + 9 ) ^{4}} d x

f (x) = \frac{375}{x ^{4}}

\frac{d}{d x} (10 x + 5)

\int 3 x^{2} e^{- x^{3}} d x

What is partialfraction (x^2)/(x^2-1) ?
The solution to partialfraction (x^2)/(x^2-1) is 1-1/(2(x+1))+1/(2(x-1))