What is the derivative of (99x^{7/2})/4 ?

The derivative of (99x^{7/2})/4 is (693x^{5/2})/8

What is the first derivative of (99x^{7/2})/4 ?

The first derivative of (99x^{7/2})/4 is (693x^{5/2})/8

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derivative of

\frac{99 x ^{\frac{7}{2}}}{4}

\frac{693 x ^{\frac{5}{2}}}{8}

Solution steps

\frac{d}{d x} (\frac{99 x ^{\frac{7}{2}}}{4})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{99}{4} \frac{d}{d x} (x^{\frac{7}{2}})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= \frac{99}{4} \cdot \frac{7}{2} x^{\frac{7}{2} - 1}

Simplify

\frac{99}{4} \cdot \frac{7}{2} x^{\frac{7}{2} - 1} : \frac{693 x ^{\frac{5}{2}}}{8}

= \frac{693 x ^{\frac{5}{2}}}{8}

\int \frac{2 x + 6}{( ( x + 1 ) ^{2} + 9 ) ^{4}} d x

f (x) = \frac{375}{x ^{4}}

\frac{d}{d x} (10 x + 5)

\int 3 x^{2} e^{- x^{3}} d x

\frac{d}{d x} (x^{2} + 4 x + 7)

What is the derivative of (99x^{7/2})/4 ?
The derivative of (99x^{7/2})/4 is (693x^{5/2})/8
What is the first derivative of (99x^{7/2})/4 ?
The first derivative of (99x^{7/2})/4 is (693x^{5/2})/8