What is the tangent of f(x)= 1/((x-5)),\at x=-3 ?

The tangent of f(x)= 1/((x-5)),\at x=-3 is y=-1/64 x-11/64

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tangent of f(x)= 1/((x-5)),\at x=-3

tangent of

f (x) = \frac{1}{( x - 5 )}, at x = - 3

y = - \frac{1}{64} x - \frac{11}{64}

Solution steps

Find the tangent point:

(- 3, - \frac{1}{8})

Find the slope of

f (x) = \frac{1}{x - 5} : \frac{df ( x )}{d x} = - \frac{1}{( x - 5 ) ^{2}}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - \frac{1}{64}

Find the line with slope m=

- \frac{1}{64}

and passing through

(- 3, - \frac{1}{8}) : y = - \frac{1}{64} x - \frac{11}{64}

y = - \frac{1}{64} x - \frac{11}{64}

\frac{2 s + 1}{s ^{2} - 2 s + 2}

\int_{2}^{3} 3 x^{2} d x

2 x + 3

\frac{d}{d x} ((1 + 1 0^{l n (x)})^{6})

\int \frac{1}{3 - 2 x - x ^{2}} d x

What is the tangent of f(x)= 1/((x-5)),\at x=-3 ?
The tangent of f(x)= 1/((x-5)),\at x=-3 is y=-1/64 x-11/64