What is the derivative of 2ln(2x+5) ?

The derivative of 2ln(2x+5) is 4/(2x+5)

What is the first derivative of 2ln(2x+5) ?

The first derivative of 2ln(2x+5) is 4/(2x+5)

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\frac{d}{d x} (2 ln (2 x + 5))

\frac{4}{2 x + 5}

Solution steps

\frac{d}{d x} (2 ln (2 x + 5))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d x} (ln (2 x + 5))

Apply the chain rule:

\frac{1}{2 x + 5} \frac{d}{d x} (2 x + 5)

= \frac{1}{2 x + 5} \frac{d}{d x} (2 x + 5)

\frac{d}{d x} (2 x + 5) = 2

= 2 \cdot \frac{1}{2 x + 5} \cdot 2

Simplify

2 \cdot \frac{1}{2 x + 5} \cdot 2 : \frac{4}{2 x + 5}

= \frac{4}{2 x + 5}

\frac{d}{d x} (\frac{x}{1 + 2 x})

\int \frac{x}{x ^{4} + 25} d x

\int \frac{5}{x} d x

y^{2} + (x^{2} \frac{d y}{d x}) = (x y) \frac{d y}{d x}

\frac{d}{d x} (\frac{x ( 2 - x )}{e ^{x}})

What is the derivative of 2ln(2x+5) ?
The derivative of 2ln(2x+5) is 4/(2x+5)
What is the first derivative of 2ln(2x+5) ?
The first derivative of 2ln(2x+5) is 4/(2x+5)