What is the derivative of y= 1/(2x-9) ?

The derivative of y= 1/(2x-9) is -2/((2x-9)^2)

What is the first derivative of y= 1/(2x-9) ?

The first derivative of y= 1/(2x-9) is -2/((2x-9)^2)

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derivative of

y = \frac{1}{2 x - 9}

- \frac{2}{( 2 x - 9 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{1}{2 x - 9})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{d}{d x} ((2 x - 9)^{- 1})

Apply the chain rule:

- \frac{1}{( 2 x - 9 ) ^{2}} \frac{d}{d x} (2 x - 9)

= - \frac{1}{( 2 x - 9 ) ^{2}} \frac{d}{d x} (2 x - 9)

\frac{d}{d x} (2 x - 9) = 2

= - \frac{1}{( 2 x - 9 ) ^{2}} \cdot 2

Simplify

- \frac{1}{( 2 x - 9 ) ^{2}} \cdot 2 : - \frac{2}{( 2 x - 9 ) ^{2}}

= - \frac{2}{( 2 x - 9 ) ^{2}}

\frac{d}{d x} (e^{- i x})

x \to 0 lim ((1 + x) \frac{1}{x})

\int \frac{15}{1 + 9 x ^{2}} d x

- 4 x + x^{2} + 10, 9 - 2 x, 2 x + 1

y = x - 2 3 x

What is the derivative of y= 1/(2x-9) ?
The derivative of y= 1/(2x-9) is -2/((2x-9)^2)
What is the first derivative of y= 1/(2x-9) ?
The first derivative of y= 1/(2x-9) is -2/((2x-9)^2)