What is the limit as x approaches 0 of (1+x) 1/x ?

The limit as x approaches 0 of (1+x) 1/x is diverges

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limit as x approaches 0 of (1+x) 1/x

x \to 0 lim ((1 + x) \frac{1}{x})

diverges

Solution steps

x \to 0 lim ((1 + x) \frac{1}{x})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 0 + lim ((1 + x) \frac{1}{x}) = \infty

x \to 0 - lim ((1 + x) \frac{1}{x}) = - \infty

= diverges

\int \frac{15}{1 + 9 x ^{2}} d x

- 4 x + x^{2} + 10, 9 - 2 x, 2 x + 1

y = x - 2 3 x

\frac{d P}{d t} = P - P^{2}

(2) (e^{3 x})

What is the limit as x approaches 0 of (1+x) 1/x ?
The limit as x approaches 0 of (1+x) 1/x is diverges