What is the tangent of f(x)=x^2-x,\at x=3 ?

The tangent of f(x)=x^2-x,\at x=3 is y=5x-9

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tangent of f(x)=x^2-x,\at x=3

tangent of

f (x) = x^{2} - x, at x = 3

y = 5 x - 9

Solution steps

Find the tangent point:

(3, 6)

Find the slope of

f (x) = x^{2} - x : \frac{df ( x )}{d x} = 2 x - 1

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 5

Find the line with slope m=

5

and passing through

(3, 6) : y = 5 x - 9

y = 5 x - 9

\int (\frac{x ^{2} + 3 x - 2}{x}) d x

lo g_{b} (x)

\frac{d}{d x} (2 sin (x) + cos (3 x))

2 x y + x^{2} (\frac{d y}{d x}) = y^{2}

x \to 4 lim (4 x + 2)

What is the tangent of f(x)=x^2-x,\at x=3 ?
The tangent of f(x)=x^2-x,\at x=3 is y=5x-9