What is the derivative of 2sin(x+cos(3x)) ?

The derivative of 2sin(x+cos(3x)) is 2cos(x)-sin(3x)*3

What is the first derivative of 2sin(x+cos(3x)) ?

The first derivative of 2sin(x+cos(3x)) is 2cos(x)-sin(3x)*3

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\frac{d}{d x} (2 sin (x) + cos (3 x))

2 cos (x) - sin (3 x) \cdot 3

Solution steps

\frac{d}{d x} (2 sin (x) + cos (3 x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 sin (x)) + \frac{d}{d x} (cos (3 x))

\frac{d}{d x} (2 sin (x)) = 2 cos (x)

\frac{d}{d x} (cos (3 x)) = - sin (3 x) \cdot 3

= 2 cos (x) - sin (3 x) \cdot 3

2 x y + x^{2} (\frac{d y}{d x}) = y^{2}

x \to 4 lim (4 x + 2)

y = x^{2} + 2 x - 3

\frac{6}{x}

y = e^{s} (s^{3} + 5), (0, 5)

What is the derivative of 2sin(x+cos(3x)) ?
The derivative of 2sin(x+cos(3x)) is 2cos(x)-sin(3x)*3
What is the first derivative of 2sin(x+cos(3x)) ?
The first derivative of 2sin(x+cos(3x)) is 2cos(x)-sin(3x)*3