What is the derivative of ce^{-2x} ?

The derivative of ce^{-2x} is -2ce^{-2x}

What is the first derivative of ce^{-2x} ?

The first derivative of ce^{-2x} is -2ce^{-2x}

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\frac{d}{d x} (c e^{- 2 x})

- 2 c e^{- 2 x}

Solution steps

\frac{d}{d x} (c e^{- 2 x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= c \frac{d}{d x} (e^{- 2 x})

Apply the chain rule:

e^{- 2 x} \frac{d}{d x} (- 2 x)

= e^{- 2 x} \frac{d}{d x} (- 2 x)

\frac{d}{d x} (- 2 x) = - 2

= c e^{- 2 x} (- 2)

Simplify

= - 2 c e^{- 2 x}

\int_{1}^{2} x^{2} - 1 d x

y^{^{'}} = \frac{( 1 - 2 x )}{y}

(x + 5) e^{2 x} + 7

\frac{d y}{d t} = 5 \cdot (y - t^{2})

\frac{\partial}{\partial x} (\frac{1}{( 1 - x ) ^{2}})

What is the derivative of ce^{-2x} ?
The derivative of ce^{-2x} is -2ce^{-2x}
What is the first derivative of ce^{-2x} ?
The first derivative of ce^{-2x} is -2ce^{-2x}