What is area y=2x^2+5x+6,(-2,0) ?

The answer to area y=2x^2+5x+6,(-2,0) is 22/3

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area y=2x^2+5x+6,(-2,0)

area

y = 2 x^{2} + 5 x + 6, (- 2, 0)

\frac{22}{3}

Decimal

7.33333 \dots

Solution steps

Apply the area formula:

\int_{- 2}^{0} 2 x^{2} + 5 x + 6 d x

Solve

\int_{- 2}^{0} 2 x^{2} + 5 x + 6 d x : \frac{22}{3}

The area is:

= \frac{22}{3}

\frac{d}{d x} (\frac{1}{2} x^{2} - \frac{1}{4} x + \frac{1}{3})

\int 4 \frac{cos ( x )}{sin ^{2} ( x )} d x

2 x^{2} - 7 x + 5

\frac{\partial}{\partial x} (C e^{2 x})

\frac{x}{x + 1}