What is the derivative of 2x^2-7x+5 ?

The derivative of 2x^2-7x+5 is 4x-7

What is the first derivative of 2x^2-7x+5 ?

The first derivative of 2x^2-7x+5 is 4x-7

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derivative of

2 x^{2} - 7 x + 5

4 x - 7

Solution steps

\frac{d}{d x} (2 x^{2} - 7 x + 5)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{2}) - \frac{d}{d x} (7 x) + \frac{d}{d x} (5)

\frac{d}{d x} (2 x^{2}) = 4 x

\frac{d}{d x} (7 x) = 7

\frac{d}{d x} (5) = 0

= 4 x - 7 + 0

Simplify

= 4 x - 7

\frac{\partial}{\partial x} (C e^{2 x})

\frac{x}{x + 1}

\frac{d}{d x} (x^{2} + 5 - 3 x^{- 2})

\int x^{5} cos (y^{4}) d x

\frac{\partial}{\partial u} (v cos (u))

What is the derivative of 2x^2-7x+5 ?
The derivative of 2x^2-7x+5 is 4x-7
What is the first derivative of 2x^2-7x+5 ?
The first derivative of 2x^2-7x+5 is 4x-7