What is the derivative of f(x)=-3x+1 ?

The derivative of f(x)=-3x+1 is -3

What is the first derivative of f(x)=-3x+1 ?

The first derivative of f(x)=-3x+1 is -3

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derivative of

f (x) = - 3 x + 1

- 3

Solution steps

\frac{d}{d x} (- 3 x + 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d x} (3 x) + \frac{d}{d x} (1)

\frac{d}{d x} (3 x) = 3

\frac{d}{d x} (1) = 0

= - 3 + 0

Simplify

= - 3

\int \frac{3 x}{3 - x ^{2}} d x

f (x) = - 5 x + 2

\frac{d y}{d x} + 4 y = 8

\int \frac{9}{x ^{3} - 3 x ^{2}} d x

y^{^{'}} + 5 y = cos (x)

What is the derivative of f(x)=-3x+1 ?
The derivative of f(x)=-3x+1 is -3
What is the first derivative of f(x)=-3x+1 ?
The first derivative of f(x)=-3x+1 is -3