What is the tangent of f(x)=x^2,(0,-9) ?

The tangent of f(x)=x^2,(0,-9) is y=6x-9 \lor y=-6x-9

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tangent of f(x)=x^2,(0,-9)

tangent of

f (x) = x^{2}, (0, - 9)

y = 6 x - 9 or y = - 6 x - 9

Solution steps

Slope of the tangent line at

(0, - 9) : m = \frac{x ^{2} + 9}{x}

Find the slope of

f (x) = x^{2} : m = 2 x

Solve

2 x = \frac{x ^{2} + 9}{x} : x = 3, x = - 3

Find the tangent line at

x = 3 : y = 6 x - 9

Find the tangent line at

x = - 3 : y = - 6 x - 9

y = 6 x - 9 or y = - 6 x - 9

sin (θ) + cos (θ)

\frac{d}{d x} (2 sec (x) tan (x))

arctan (x), 0

\int \frac{e ^{c o s (x)}}{csc ( x )} d x

y y^{^{'}} = - t

What is the tangent of f(x)=x^2,(0,-9) ?
The tangent of f(x)=x^2,(0,-9) is y=6x-9 \lor y=-6x-9