What is the f(x)=(x-4)/(x^2) ?

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f(x)=(x-4)/(x^2)

f (x) = \frac{x - 4}{x ^{2}}

Domain : x < 0 or x > 0

Range : f (x) \leq \frac{1}{16}

X Intercepts : (4, 0)

Asymptotes : Vertical x = 0, Horizontal y = 0

Extreme Points : Maximum (8, \frac{1}{16})

Interval Notation

Domain : (- \infty, 0) \cup (0, \infty)

Range : (- \infty, \frac{1}{16}]

Solution steps

Domain of

\frac{x - 4}{x ^{2}} : x < 0 or x > 0

Range of

\frac{x - 4}{x ^{2}} : f (x) \leq \frac{1}{16}

Axis interception points of

\frac{x - 4}{x ^{2}} :

X Intercepts

: (4, 0)

Asymptotes of

\frac{x - 4}{x ^{2}} :

Vertical

: x = 0,

Horizontal

: y = 0

Extreme Points of

\frac{x - 4}{x ^{2}} :

Maximum

(8, \frac{1}{16})

\int \frac{sec ^{3} ( θ )}{tan ( θ )} d θ

f (x) = 16 cos (2 x)

(e^{x} + y) d x + (2 + x + y e^{y}) d y = 0, y (0) = 1

n = 0 \sum \infty n \cdot (n + 1) \cdot x^{n}

\int \frac{1}{16 + 6 x - x ^{2}} d x