What is the derivative of f(x)=16cos(2x) ?

The derivative of f(x)=16cos(2x) is -32sin(2x)

What is the first derivative of f(x)=16cos(2x) ?

The first derivative of f(x)=16cos(2x) is -32sin(2x)

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derivative of

f (x) = 16 cos (2 x)

- 32 sin (2 x)

Solution steps

\frac{d}{d x} (16 cos (2 x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 16 \frac{d}{d x} (cos (2 x))

Apply the chain rule:

- sin (2 x) \frac{d}{d x} (2 x)

= - sin (2 x) \frac{d}{d x} (2 x)

\frac{d}{d x} (2 x) = 2

= 16 (- sin (2 x) \cdot 2)

Simplify

= - 32 sin (2 x)

(e^{x} + y) d x + (2 + x + y e^{y}) d y = 0, y (0) = 1

n = 0 \sum \infty n \cdot (n + 1) \cdot x^{n}

\int \frac{1}{16 + 6 x - x ^{2}} d x

\frac{\partial}{\partial x} (\frac{y ^{4}}{x})

(2 t - 1) (3 t - 3)^{- 1}

What is the derivative of f(x)=16cos(2x) ?
The derivative of f(x)=16cos(2x) is -32sin(2x)
What is the first derivative of f(x)=16cos(2x) ?
The first derivative of f(x)=16cos(2x) is -32sin(2x)