What is (\partial)/(\partial x)(sin(x)+cos(-6y)) ?

The answer to (\partial)/(\partial x)(sin(x)+cos(-6y)) is cos(x)

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(\partial)/(\partial x)(sin(x)+cos(-6y))

\frac{\partial}{\partial x} (sin (x) + cos (- 6 y))

cos (x)

Solution steps

\frac{\partial}{\partial x} (sin (x) + cos (- 6 y))

Simplify

sin (x) + cos (- 6 y) : cos (6 y) + sin (x)

= \frac{\partial}{\partial x} (cos (6 y) + sin (x))

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (cos (6 y)) + \frac{\partial}{\partial x} (sin (x))

\frac{\partial}{\partial x} (cos (6 y)) = 0

\frac{\partial}{\partial x} (sin (x)) = cos (x)

= 0 + cos (x)

Simplify

= cos (x)

\frac{\partial}{\partial x} (\frac{5 x y ^{2}}{x ^{2} + y ^{4}})

\frac{20}{s \cdot ( s + 10 )}

\int x^{3} - 2.5 x + 1 d x

t \to 7 lim \frac{( t - 7 ) ^{3}}{t - 7}

\frac{\partial}{\partial x} ((2 x - 3 y)^{3})

What is (\partial)/(\partial x)(sin(x)+cos(-6y)) ?
The answer to (\partial)/(\partial x)(sin(x)+cos(-6y)) is cos(x)