What is the solution for y^{''}+25y=te^{6t} ?

The solution for y^{''}+25y=te^{6t} is y=c_{1}cos(5t)+c_{2}sin(5t)+(e^{6t}t)/(61)-12/3721 e^{6t}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^{''}+25y=te^{6t}

y^{^{''}} + 25 y = t e^{6 t}

y = c_{1} cos (5 t) + c_{2} sin (5 t) + \frac{e ^{6 t} t}{61} - \frac{12}{3721} e^{6 t}

Solution steps

y^{''} (t) + 25 y = t e^{6 t}

Solve linear ODE:

y = c_{1} cos (5 t) + c_{2} sin (5 t) + \frac{e ^{6 t} t}{61} - \frac{12}{3721} e^{6 t}

y = c_{1} cos (5 t) + c_{2} sin (5 t) + \frac{e ^{6 t} t}{61} - \frac{12}{3721} e^{6 t}

\frac{d y}{d x}, x y = 3

\frac{d}{d x} (e^{x + c})

2 y^{^{''}} + 13 y^{^{'}} - 7 y = 0

\int \frac{1}{x ^{2} + t ^{2}} d x

What is the solution for y^{''}+25y=te^{6t} ?
The solution for y^{''}+25y=te^{6t} is y=c_{1}cos(5t)+c_{2}sin(5t)+(e^{6t}t)/(61)-12/3721 e^{6t}