What is the derivative of 3sin(-5x) ?

The derivative of 3sin(-5x) is -15cos(5x)

What is the first derivative of 3sin(-5x) ?

The first derivative of 3sin(-5x) is -15cos(5x)

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derivative of

3 sin (- 5 x)

- 15 cos (5 x)

Solution steps

\frac{d}{d x} (3 sin (- 5 x))

Simplify

3 sin (- 5 x) : - 3 sin (5 x)

= \frac{d}{d x} (- 3 sin (5 x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 3 \frac{d}{d x} (sin (5 x))

Apply the chain rule:

cos (5 x) \frac{d}{d x} (5 x)

= cos (5 x) \frac{d}{d x} (5 x)

\frac{d}{d x} (5 x) = 5

= - 3 cos (5 x) \cdot 5

Simplify

= - 15 cos (5 x)

n = 1 \sum \infty \frac{70}{7 ^{n}}

\int sec^{4} (\frac{x}{2}) d x

\int_{0}^{3} 30 (25 - t^{2}) d t

x \to \infty lim (∣ x + 2 ∣)

\int_{0}^{\infty} \frac{1}{2 x + 5} d x

What is the derivative of 3sin(-5x) ?
The derivative of 3sin(-5x) is -15cos(5x)
What is the first derivative of 3sin(-5x) ?
The first derivative of 3sin(-5x) is -15cos(5x)