What is the derivative of f(x)=ln(x-1) ?

The derivative of f(x)=ln(x-1) is 1/(x-1)

What is the first derivative of f(x)=ln(x-1) ?

The first derivative of f(x)=ln(x-1) is 1/(x-1)

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derivative of

f (x) = ln (x - 1)

\frac{1}{x - 1}

Solution steps

\frac{d}{d x} (ln (x - 1))

Apply the chain rule:

\frac{1}{x - 1} \frac{d}{d x} (x - 1)

= \frac{1}{x - 1} \frac{d}{d x} (x - 1)

\frac{d}{d x} (x - 1) = 1

= \frac{1}{x - 1} \cdot 1

Simplify

= \frac{1}{x - 1}

\int (12 x^{2} - 8 x + 2) d x

\frac{d y}{d x} = \frac{( x - 1 )}{y}

\frac{d}{d x} (7 arcsin (x^{2}))

y = 1 x, (0, 4)

t \frac{d y}{d t} + 9 y = \frac{1}{t}

What is the derivative of f(x)=ln(x-1) ?
The derivative of f(x)=ln(x-1) is 1/(x-1)
What is the first derivative of f(x)=ln(x-1) ?
The first derivative of f(x)=ln(x-1) is 1/(x-1)