What is the derivative of 5ln(\sqrt[5]{e^{x^3}}) ?

The derivative of 5ln(\sqrt[5]{e^{x^3}}) is (3e^{(x^3)/5}x^2)/(\sqrt[5]{e^{x^3)}}

What is the first derivative of 5ln(\sqrt[5]{e^{x^3}}) ?

The first derivative of 5ln(\sqrt[5]{e^{x^3}}) is (3e^{(x^3)/5}x^2)/(\sqrt[5]{e^{x^3)}}

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Solution steps

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

Apply the chain rule:

Simplify

\int (x^{2} + 2 x) cos (x^{3} + 3 x^{2} - 47) d x

(7 x + 8) (8 x - 9)

y = \frac{x}{4 + x}

n = 1 \sum \infty \frac{4}{n ( n + 3 ) !}

\int 3 x^{2} y d x

What is the derivative of 5ln(\sqrt[5]{e^{x^3}}) ?
The derivative of 5ln(\sqrt[5]{e^{x^3}}) is (3e^{(x^3)/5}x^2)/(\sqrt[5]{e^{x^3)}}
What is the first derivative of 5ln(\sqrt[5]{e^{x^3}}) ?
The first derivative of 5ln(\sqrt[5]{e^{x^3}}) is (3e^{(x^3)/5}x^2)/(\sqrt[5]{e^{x^3)}}