What is the derivative of (7x+8)(8x-9) ?

The derivative of (7x+8)(8x-9) is 112x+1

What is the first derivative of (7x+8)(8x-9) ?

The first derivative of (7x+8)(8x-9) is 112x+1

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derivative of

(7 x + 8) (8 x - 9)

112 x + 1

Solution steps

\frac{d}{d x} ((7 x + 8) (8 x - 9))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = 7 x + 8, g = 8 x - 9

= \frac{d}{d x} (7 x + 8) (8 x - 9) + \frac{d}{d x} (8 x - 9) (7 x + 8)

\frac{d}{d x} (7 x + 8) = 7

\frac{d}{d x} (8 x - 9) = 8

= 7 (8 x - 9) + 8 (7 x + 8)

Simplify

7 (8 x - 9) + 8 (7 x + 8) : 112 x + 1

= 112 x + 1

y = \frac{x}{4 + x}

n = 1 \sum \infty \frac{4}{n ( n + 3 ) !}

\int 3 x^{2} y d x

\frac{d}{d x} (\frac{x ^{2} + 1}{x ^{2} + 4})

What is the derivative of (7x+8)(8x-9) ?
The derivative of (7x+8)(8x-9) is 112x+1
What is the first derivative of (7x+8)(8x-9) ?
The first derivative of (7x+8)(8x-9) is 112x+1