What is the integral of (3sin(t)-2cos(t)) ?

The integral of (3sin(t)-2cos(t)) is -3cos(t)-2sin(t)+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of (3sin(t)-2cos(t))

\int (3 sin (t) - 2 cos (t)) d t

- 3 cos (t) - 2 sin (t) + C

Solution steps

\int 3 sin (t) - 2 cos (t) d t

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 3 sin (t) d t - \int 2 cos (t) d t

\int 3 sin (t) d t = - 3 cos (t)

\int 2 cos (t) d t = 2 sin (t)

= - 3 cos (t) - 2 sin (t)

Add a constant to the solution

= - 3 cos (t) - 2 sin (t) + C

\int \frac{9 - x ^{2}}{x ^{2}} d x

\frac{\partial}{\partial x} (b lo g_{10} (x))

\frac{\partial}{\partial x} ((x_{1} + x_{2})^{2})

\int_{0}^{9} π (y^{\frac{3}{2}})^{2} d y

What is the integral of (3sin(t)-2cos(t)) ?
The integral of (3sin(t)-2cos(t)) is -3cos(t)-2sin(t)+C