What is (\partial)/(\partial x)(blog_{10}(x)) ?

The answer to (\partial)/(\partial x)(blog_{10}(x)) is b/(ln(10)x)

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(\partial)/(\partial x)(blog_{10}(x))

\frac{\partial}{\partial x} (b lo g_{10} (x))

\frac{b}{ln ( 10 ) x}

Solution steps

\frac{\partial}{\partial x} (b lo g_{10} (x))

Treat

b

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= b \frac{\partial}{\partial x} (lo g_{10} (x))

Apply the derivative log rule:

\frac{d}{d x} (lo g_{a} (x)) = \frac{1}{x ln ( a )}

= b \frac{1}{x ln ( 10 )}

Simplify

b \frac{1}{x ln ( 10 )} : \frac{b}{ln ( 10 ) x}

= \frac{b}{ln ( 10 ) x}

\frac{\partial}{\partial x} ((x_{1} + x_{2})^{2})

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n = 0 \sum \infty \frac{5 ^{n}}{4 ^{n}}

\frac{d}{d x} (\frac{x ^{\frac{7}{3}} + 3 x ^{3} - 8}{6 x ^{2}})

What is (\partial)/(\partial x)(blog_{10}(x)) ?
The answer to (\partial)/(\partial x)(blog_{10}(x)) is b/(ln(10)x)