What is (\partial)/(\partial y)(x^2sin(2y)) ?

The answer to (\partial)/(\partial y)(x^2sin(2y)) is x^2cos(2y)*2

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(\partial)/(\partial y)(x^2sin(2y))

\frac{\partial}{\partial y} (x^{2} sin (2 y))

x^{2} cos (2 y) \cdot 2

Solution steps

\frac{\partial}{\partial y} (x^{2} sin (2 y))

Treat

x

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= x^{2} \frac{\partial}{\partial y} (sin (2 y))

Apply the chain rule:

cos (2 y) \frac{\partial}{\partial y} (2 y)

= cos (2 y) \frac{\partial}{\partial y} (2 y)

\frac{\partial}{\partial y} (2 y) = 2

= x^{2} cos (2 y) \cdot 2

x \to - 6 lim (x - 6 - x)

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\frac{\partial}{\partial y} (- arctan (\frac{x}{y}))

\frac{3 ^{2}}{s ( s + 3 ) ^{2}}

\int (7 x^{2} + 4 x^{- 2}) d x

What is (\partial)/(\partial y)(x^2sin(2y)) ?
The answer to (\partial)/(\partial y)(x^2sin(2y)) is x^2cos(2y)*2