What is the integral of e^x(sin(x)) ?

The integral of e^x(sin(x)) is -(e^xcos(x))/2+(e^xsin(x))/2+C

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integral of e^x(sin(x))

\int e^{x} (sin (x)) d x

- \frac{e ^{x} cos ( x )}{2} + \frac{e ^{x} sin ( x )}{2} + C

Solution steps

\int e^{x} sin (x) d x

Apply Integration By Parts

: - e^{x} cos (x) - \int - e^{x} cos (x) d x

= - e^{x} cos (x) - \int - e^{x} cos (x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - e^{x} cos (x) - (- \int e^{x} cos (x) d x)

Apply Integration By Parts

: e^{x} sin (x) - \int e^{x} sin (x) d x

= - e^{x} cos (x) - (- (e^{x} sin (x) - \int e^{x} sin (x) d x))

Therefore

\int e^{x} sin (x) d x = - e^{x} cos (x) - (- (e^{x} sin (x) - \int e^{x} sin (x) d x))

Isolate

\int e^{x} sin (x) d x

= - \frac{e ^{x} cos ( x )}{2} + \frac{e ^{x} sin ( x )}{2}

Add a constant to the solution

= - \frac{e ^{x} cos ( x )}{2} + \frac{e ^{x} sin ( x )}{2} + C

\frac{2}{s ( s ^{2} + 4 s )}

\int_{6}^{8} \frac{84}{( x - 6 ) ^{3}} d x

\frac{d y}{d x} = 2 y sin (x)

2 x y \frac{d y}{d x} + x^{2} - y^{2} = 0

f (x) = x, (9, 3)

What is the integral of e^x(sin(x)) ?
The integral of e^x(sin(x)) is -(e^xcos(x))/2+(e^xsin(x))/2+C