What is (\partial)/(\partial y)(2y^2x) ?

The answer to (\partial)/(\partial y)(2y^2x) is 4yx

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(\partial)/(\partial y)(2y^2x)

\frac{\partial}{\partial y} (2 y^{2} x)

4 y x

Solution steps

\frac{\partial}{\partial y} (2 y^{2} x)

Treat

x

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 x \frac{\partial}{\partial y} (y^{2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 2 x \cdot 2 y^{2 - 1}

Simplify

= 4 y x

x \to 8 lim (\frac{3 x ^{2} - 24 x}{x ^{2} - 64})

x \to 2 lim (\frac{( x + 1 )}{x - 2})

\frac{d}{d x} (2 x - sin (2 x))

\frac{d}{d x} (x^{3} - 3 x + 3)

f (x) = \frac{2}{x}, at x = \frac{1}{16}

What is (\partial)/(\partial y)(2y^2x) ?
The answer to (\partial)/(\partial y)(2y^2x) is 4yx