What is (\partial)/(\partial x)(I/(2x)) ?

The answer to (\partial)/(\partial x)(I/(2x)) is -I/(2x^2)

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(\partial)/(\partial x)(I/(2x))

\frac{\partial}{\partial x} (\frac{I}{2 x})

- \frac{I}{2 x ^{2}}

Solution steps

\frac{\partial}{\partial x} (\frac{I}{2 x})

Treat

I

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{I}{2} \frac{\partial}{\partial x} (\frac{1}{x})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{I}{2} \frac{\partial}{\partial x} (x^{- 1})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= \frac{I}{2} (- 1 \cdot x^{- 1 - 1})

Simplify

\frac{I}{2} (- 1 \cdot x^{- 1 - 1}) : - \frac{I}{2 x ^{2}}

= - \frac{I}{2 x ^{2}}

\frac{\partial}{\partial x} (2 x^{2} e^{y})

\frac{d}{d x} ((x^{2} + 4)^{- 2})

\frac{d y}{d t} = b (1 - y) y

\int 17 arctan (x) d x

x \to - 9 + lim (3 x^{2} - 4 x - 7)

What is (\partial)/(\partial x)(I/(2x)) ?
The answer to (\partial)/(\partial x)(I/(2x)) is -I/(2x^2)