What is laplacetransform 3te^{-t} ?

The answer to laplacetransform 3te^{-t} is 3/((s+1)^2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

laplacetransform 3te^{-t}

laplace transform

3 t e^{- t}

\frac{3}{( s + 1 ) ^{2}}

Solution steps

L {3 e^{- t} t}

Use the constant multiplication property of Laplace Transform:

For function

f (t)

and constant

a : L {a \cdot f (t)} = a \cdot L {f (t)}

= 3 L {t e^{- t}}

L {t e^{- t}} : \frac{1}{( s + 1 ) ^{2}}

= 3 \cdot \frac{1}{( s + 1 ) ^{2}}

Refine

3 \frac{1}{( s + 1 ) ^{2}} : \frac{3}{( s + 1 ) ^{2}}

= \frac{3}{( s + 1 ) ^{2}}

\int_{2}^{e + 1} \frac{1}{x - 1} d x

\int cos^{3} (4 x) sin (4 x) d x

\frac{d y}{d x} + tan (x) y - sec (x) = 0

\frac{d}{d x} (26 - sec^{3} (4 x))

x \to \infty lim ((4^{x} + 8^{x})^{\frac{1}{2 \cdot x}})

What is laplacetransform 3te^{-t} ?
The answer to laplacetransform 3te^{-t} is 3/((s+1)^2)