What is the solution for (dy)/(dx)+tan(x)y-sec(x)=0 ?

The solution for (dy)/(dx)+tan(x)y-sec(x)=0 is y=(tan(x))/(sec(x))+(c_{1})/(sec(x))

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(dy)/(dx)+tan(x)y-sec(x)=0

\frac{d y}{d x} + tan (x) y - sec (x) = 0

y = \frac{tan ( x )}{sec ( x )} + \frac{c _{1}}{sec ( x )}

Solution steps

\frac{d y}{d x} + tan (x) y - sec (x) = 0

Solve linear ODE:

y = \frac{tan ( x )}{sec ( x )} + \frac{c _{1}}{sec ( x )}

y = \frac{tan ( x )}{sec ( x )} + \frac{c _{1}}{sec ( x )}

\frac{d}{d x} (26 - sec^{3} (4 x))

x \to \infty lim ((4^{x} + 8^{x})^{\frac{1}{2 \cdot x}})

\frac{d}{d x} (- x cos (x) + x)

\frac{\partial}{\partial y} (x^{4} + y^{4} + 3 x^{2} y^{3})

\frac{\partial}{\partial x} (x e^{- x^{2}})

What is the solution for (dy)/(dx)+tan(x)y-sec(x)=0 ?
The solution for (dy)/(dx)+tan(x)y-sec(x)=0 is y=(tan(x))/(sec(x))+(c_{1})/(sec(x))