What is the sum from n=0 to infinity of (-1^n)/(n!) ?

The sum from n=0 to infinity of (-1^n)/(n!) is converges

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sum from n=0 to infinity of (-1^n)/(n!)

n = 0 \sum \infty \frac{- 1 ^{n}}{n !}

converges

Solution steps

n = 0 \sum \infty \frac{- 1 ^{n}}{n !}

Apply the constant multiplication rule:

\sum c \cdot a_{n} = c \cdot \sum a_{n}

= - n = 0 \sum \infty \frac{1 ^{n}}{n !}

Apply Series Ratio Test:

converges

= - converges

= converges

y = x^{10} + 1 + 1 - x

\frac{d}{d x} (9 x + 4)

\int (4 sec (x) tan (x) - 2 sec^{2} (x)) d x

\int 10 25 - x d x

x y^{2}

What is the sum from n=0 to infinity of (-1^n)/(n!) ?
The sum from n=0 to infinity of (-1^n)/(n!) is converges