What is the limit as x approaches-infinity of 2^{-x} ?

The limit as x approaches-infinity of 2^{-x} is infinity

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

limit as x approaches-infinity of 2^{-x}

x \to - \infty lim (2^{- x})

\infty

Solution steps

x \to - \infty lim (2^{- x})

Apply exponent rules

= x \to - \infty lim (e^{- x l n (2)})

Apply the Limit Chain Rule:

\infty

= \infty

\frac{2 x}{9 x ^{2} + 1}

y = \frac{x}{x + 2}, (4, \frac{2}{6})

- 2 x^{5} + 3 x^{2} - 7

\frac{\partial}{\partial x} (4 - 2 y + 4 x y)

\int (x + \frac{1}{x}) d x

What is the limit as x approaches-infinity of 2^{-x} ?
The limit as x approaches-infinity of 2^{-x} is infinity