What is (\partial)/(\partial x)(x^2-2x^2y-5xy^2) ?

The answer to (\partial)/(\partial x)(x^2-2x^2y-5xy^2) is 2x-4yx-5y^2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial x)(x^2-2x^2y-5xy^2)

\frac{\partial}{\partial x} (x^{2} - 2 x^{2} y - 5 x y^{2})

2 x - 4 y x - 5 y^{2}

Solution steps

\frac{\partial}{\partial x} (x^{2} - 2 x^{2} y - 5 x y^{2})

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (x^{2}) - \frac{\partial}{\partial x} (2 x^{2} y) - \frac{\partial}{\partial x} (5 x y^{2})

\frac{\partial}{\partial x} (x^{2}) = 2 x

\frac{\partial}{\partial x} (2 x^{2} y) = 4 y x

\frac{\partial}{\partial x} (5 x y^{2}) = 5 y^{2}

= 2 x - 4 y x - 5 y^{2}

\int (2 x)^{2} (5 + 3^{4})^{\frac{1}{4}} d x

tan (2 x + 5)

\int 2 + tan^{2} (x) d x

x \to \infty + lim (6 x)

What is (\partial)/(\partial x)(x^2-2x^2y-5xy^2) ?
The answer to (\partial)/(\partial x)(x^2-2x^2y-5xy^2) is 2x-4yx-5y^2