What is the derivative of f(x)=200+7/x+(x^2)/7 ?

The derivative of f(x)=200+7/x+(x^2)/7 is (2x)/7-7/(x^2)

What is the first derivative of f(x)=200+7/x+(x^2)/7 ?

The first derivative of f(x)=200+7/x+(x^2)/7 is (2x)/7-7/(x^2)

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derivative of

f (x) = 200 + \frac{7}{x} + \frac{x ^{2}}{7}

\frac{2 x}{7} - \frac{7}{x ^{2}}

Solution steps

\frac{d}{d x} (200 + \frac{7}{x} + \frac{x ^{2}}{7})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (200) + \frac{d}{d x} (\frac{7}{x}) + \frac{d}{d x} (\frac{x ^{2}}{7})

\frac{d}{d x} (200) = 0

\frac{d}{d x} (\frac{7}{x}) = - \frac{7}{x ^{2}}

\frac{d}{d x} (\frac{x ^{2}}{7}) = \frac{2 x}{7}

= 0 - \frac{7}{x ^{2}} + \frac{2 x}{7}

Simplify

= \frac{2 x}{7} - \frac{7}{x ^{2}}

y^{^{'}} = x (9 - y)

n = 1 \sum \infty \frac{1}{n + 9}

\int \frac{( x - 4 ) ^{2} ( x + 1 )}{x} d x

x y^{^{'}} = 2 y + 8 x

\int_{2}^{3} \frac{x ^{2} + 1}{x ^{3} + 3 x} d x

What is the derivative of f(x)=200+7/x+(x^2)/7 ?
The derivative of f(x)=200+7/x+(x^2)/7 is (2x)/7-7/(x^2)
What is the first derivative of f(x)=200+7/x+(x^2)/7 ?
The first derivative of f(x)=200+7/x+(x^2)/7 is (2x)/7-7/(x^2)