What is the integral from 1 to 4 of 7/(x^2) ?

The integral from 1 to 4 of 7/(x^2) is 21/4

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integral from 1 to 4 of 7/(x^2)

\int_{1}^{4} \frac{7}{x ^{2}} d x

\frac{21}{4}

Decimal Notation

5.25

Solution steps

\int_{1}^{4} \frac{7}{x ^{2}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 7 \cdot \int_{1}^{4} \frac{1}{x ^{2}} d x

Apply the Power Rule

: [- \frac{1}{x}]_{1}^{4}

= 7 [- \frac{1}{x}]_{1}^{4}

Compute the boundaries:

\frac{3}{4}

= 7 \cdot \frac{3}{4}

Simplify

= \frac{21}{4}

(9 x + 3) + (9 y - 9) y^{^{'}} = 0

\int_{0}^{3} (x + 9 - x^{2}) d x

\int_{1}^{2} cos (x^{2}) d x

\frac{\partial}{\partial y} (x^{2} + x y)

\frac{d}{d x} (\frac{9 x}{x})

What is the integral from 1 to 4 of 7/(x^2) ?
The integral from 1 to 4 of 7/(x^2) is 21/4