What is the tangent of f(x)=x^2+x+9,\at x=2 ?

The tangent of f(x)=x^2+x+9,\at x=2 is y=5x+5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of f(x)=x^2+x+9,\at x=2

tangent of

f (x) = x^{2} + x + 9, at x = 2

y = 5 x + 5

Solution steps

Find the tangent point:

(2, 15)

Find the slope of

f (x) = x^{2} + x + 9 : \frac{df ( x )}{d x} = 2 x + 1

Compute the slope of

f (x) = x^{2} + x + 9

x = 2 : m = 5

Find the line with slope m=

5

and passing through

(2, 15) : y = 5 x + 5

y = 5 x + 5

\int 5 e^{3 x} d x

h (w) = \frac{( x + 1 ) e ^{x}}{w - 2}

f (x) = 5 x^{2} - 5 x

\int \frac{2 x}{x - 4} d x

(x^{2} + 5) d x + (y - 3) (x - 2) d y = 0

What is the tangent of f(x)=x^2+x+9,\at x=2 ?
The tangent of f(x)=x^2+x+9,\at x=2 is y=5x+5