What is the limit as x approaches 1-of (2x+1)/(x-1) ?

The limit as x approaches 1-of (2x+1)/(x-1) is -infinity

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limit as x approaches 1-of (2x+1)/(x-1)

x \to 1 - lim (\frac{2 x + 1}{x - 1})

- \infty

Solution steps

x \to 1 - lim (\frac{2 x + 1}{x - 1})

\frac{2 x + 1}{x - 1} = (2 x + 1) \frac{1}{x - 1}

= x \to 1 - lim ((2 x + 1) \frac{1}{x - 1})

x \to a lim [f (x) \cdot g (x)] = x \to a lim f (x) \cdot x \to a lim g (x)

With the exception of indeterminate form

= x \to 1 - lim (2 x + 1) \cdot x \to 1 - lim (\frac{1}{x - 1})

x \to 1 - lim (2 x + 1) = 3

x \to 1 - lim (\frac{1}{x - 1}) = - \infty

= 3 (- \infty)

Apply Infinity Property:

c \cdot (- \infty) = - \infty

= - \infty

\int (4 e^{x} + 12 x^{3} + 4 x) d x

\frac{d ^{2}}{d x ^{2}} (3 ln (sec (x) + tan (x)))

\int_{- 1}^{1} cos (x) d x

y^{^{''}} + 2 y = e^{x} + x^{3}

f (x) = sin^{6} (x)

What is the limit as x approaches 1-of (2x+1)/(x-1) ?
The limit as x approaches 1-of (2x+1)/(x-1) is -infinity