What is the integral from-1 to 1 of cos(x) ?

The integral from-1 to 1 of cos(x) is 2sin(1)

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integral from-1 to 1 of cos(x)

\int_{- 1}^{1} cos (x) d x

2 sin (1)

Decimal Notation

1.68294 \dots

Solution steps

\int_{- 1}^{1} cos (x) d x

Use the common integral:

\int cos (x) d x = sin (x)

= [sin (x)]_{- 1}^{1}

Compute the boundaries:

2 sin (1)

= 2 sin (1)

y^{^{''}} + 2 y = e^{x} + x^{3}

f (x) = sin^{6} (x)

\int \frac{e ^{x}}{1 - 4 e ^{2 x}} d x

\frac{1.5}{( ( s + 1 ) )}

y^{^{'}} = e^{4 y} sin (5 x)

What is the integral from-1 to 1 of cos(x) ?
The integral from-1 to 1 of cos(x) is 2sin(1)