What is the solution for y^'=e^{4y}sin(5x) ?

The solution for y^'=e^{4y}sin(5x) is y=-(ln(4/5 cos(5x)-c_{1}))/4

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y^'=e^{4y}sin(5x)

y^{^{'}} = e^{4 y} sin (5 x)

y = - \frac{ln ( \frac{4}{5} cos ( 5 x ) - c _{1} )}{4}

Solution steps

y^{'} (x) = e^{4 y} sin (5 x)

Solve separable ODE:

y = - \frac{ln ( \frac{4}{5} cos ( 5 x ) - c _{1} )}{4}

y = - \frac{ln ( \frac{4}{5} cos ( 5 x ) - c _{1} )}{4}

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What is the solution for y^'=e^{4y}sin(5x) ?
The solution for y^'=e^{4y}sin(5x) is y=-(ln(4/5 cos(5x)-c_{1}))/4