What is the solution for (dy)/(dx)+(2x)/((1+x^2))y=-2xy^2 ?

The solution for (dy)/(dx)+(2x)/((1+x^2))y=-2xy^2 is y= 1/((x^2+1)(ln(x^2+1)+c_{1))}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(dy)/(dx)+(2x)/((1+x^2))y=-2xy^2

\frac{d y}{d x} + \frac{2 x}{( 1 + x ^{2} )} y = - 2 x y^{2}

y = \frac{1}{( x ^{2} + 1 ) ( ln ( x ^{2} + 1 ) + c _{1} )}

Solution steps

\frac{d y}{d x} + \frac{2 x}{( 1 + x ^{2} )} y = - 2 x y^{2}

Solve Bernoulli ODE:

y = \frac{1}{( x ^{2} + 1 ) ( ln ( x ^{2} + 1 ) + c _{1} )}

y = \frac{1}{( x ^{2} + 1 ) ( ln ( x ^{2} + 1 ) + c _{1} )}

\frac{d}{d x} (1 - x e^{x})

x^{2}, x + 2, y = 0

\frac{d}{d x} ((1 - x)^{3})

y = sec^{2} (x) - tan^{2} (x)

x \to \infty lim (A^{x})

What is the solution for (dy)/(dx)+(2x)/((1+x^2))y=-2xy^2 ?
The solution for (dy)/(dx)+(2x)/((1+x^2))y=-2xy^2 is y= 1/((x^2+1)(ln(x^2+1)+c_{1))}