What is the derivative of (4x+7)^2 ?

The derivative of (4x+7)^2 is 8(4x+7)

What is the first derivative of (4x+7)^2 ?

The first derivative of (4x+7)^2 is 8(4x+7)

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derivative of

(4 x + 7)^{2}

8 (4 x + 7)

Solution steps

\frac{d}{d x} ((4 x + 7)^{2})

Apply the chain rule:

2 (4 x + 7) \frac{d}{d x} (4 x + 7)

= 2 (4 x + 7) \frac{d}{d x} (4 x + 7)

\frac{d}{d x} (4 x + 7) = 4

= 2 (4 x + 7) \cdot 4

Simplify

= 8 (4 x + 7)

\int \frac{1}{2 - x ^{2}} d x

\frac{d}{d x} (\frac{x + 4}{x - 1})

\frac{d}{d x} (ln (5 x + 2))

x + 12

\frac{\partial}{\partial x} (- \frac{2 y}{3 + 2 x})

What is the derivative of (4x+7)^2 ?
The derivative of (4x+7)^2 is 8(4x+7)
What is the first derivative of (4x+7)^2 ?
The first derivative of (4x+7)^2 is 8(4x+7)