What is the derivative of (sin(10x)/(cos(10x))) ?

The derivative of (sin(10x)/(cos(10x))) is sec^2(10x)*10

What is the first derivative of (sin(10x)/(cos(10x))) ?

The first derivative of (sin(10x)/(cos(10x))) is sec^2(10x)*10

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\frac{d}{d x} (\frac{sin ( 10 x )}{cos ( 10 x )})

sec^{2} (10 x) \cdot 10

Solution steps

\frac{d}{d x} (\frac{sin ( 10 x )}{cos ( 10 x )})

Simplify

\frac{sin ( 10 x )}{cos ( 10 x )} : tan (10 x)

= \frac{d}{d x} (tan (10 x))

Apply the chain rule:

sec^{2} (10 x) \frac{d}{d x} (10 x)

= sec^{2} (10 x) \frac{d}{d x} (10 x)

\frac{d}{d x} (10 x) = 10

= sec^{2} (10 x) \cdot 10

y^{^{'}} - y = 2 t e^{2} t

\frac{d}{d x} (cos (x) + x^{2} sin (x))

\frac{\partial}{\partial y} (x e^{5 y})

\frac{d}{d x} ((cos (x) + 2)^{3} (2 x)^{- 3 x})

What is the derivative of (sin(10x)/(cos(10x))) ?
The derivative of (sin(10x)/(cos(10x))) is sec^2(10x)*10
What is the first derivative of (sin(10x)/(cos(10x))) ?
The first derivative of (sin(10x)/(cos(10x))) is sec^2(10x)*10