What is the solution for y^'=0.0015y(400-y) ?

The solution for y^'=0.0015y(400-y) is y=(0.6)/(-e^{-0.6t-c_{1)}+0.0015}

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y^'=0.0015y(400-y)

y^{^{'}} = 0.0015 y (400 - y)

y = \frac{0.6}{- e ^{- 0.6 t - c_{1}} + 0.0015}

Solution steps

y^{'} (t) = 0.0015 y (400 - y)

Solve Bernoulli ODE:

y = \frac{0.6}{- e ^{- 0.6 t - c_{1}} + 0.0015}

y = \frac{0.6}{- e ^{- 0.6 t - c_{1}} + 0.0015}

x \to + 0 lim ((1 - 2 x)^{\frac{3}{x}})

\frac{d}{d x} (b x^{2} (x - 4))

\frac{d}{d x} (\frac{x ^{2}}{x ^{2} + 3})

x \to 1 lim (10 x + 1)

\int x (x^{2} + 2)^{2} d x

What is the solution for y^'=0.0015y(400-y) ?
The solution for y^'=0.0015y(400-y) is y=(0.6)/(-e^{-0.6t-c_{1)}+0.0015}