What is the solution for (x^2+1)(dy)/(dx)+3x(y-1)=0,y(0)=4 ?

The solution for (x^2+1)(dy)/(dx)+3x(y-1)=0,y(0)=4 is y= 3/((x^2+1)^{3/2)}+1

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(x^2+1)(dy)/(dx)+3x(y-1)=0,y(0)=4

(x^{2} + 1) \frac{d y}{d x} + 3 x (y - 1) = 0, y (0) = 4

y = \frac{3}{( x ^{2} + 1 ) ^{\frac{3}{2}}} + 1

Solution steps

(x^{2} + 1) \frac{d y}{d x} + 3 x (y - 1) = 0

Solve separable ODE:

y = \frac{3}{( x ^{2} + 1 ) ^{\frac{3}{2}}} + 1

y = \frac{3}{( x ^{2} + 1 ) ^{\frac{3}{2}}} + 1

\frac{\partial}{\partial x} (x cos (y ln (x)))

x \to 0.1 lim (\frac{1}{x})

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What is the solution for (x^2+1)(dy)/(dx)+3x(y-1)=0,y(0)=4 ?
The solution for (x^2+1)(dy)/(dx)+3x(y-1)=0,y(0)=4 is y= 3/((x^2+1)^{3/2)}+1