What is the integral of t^2e^t ?

The integral of t^2e^t is t^2e^t-2(e^tt-e^t)+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of t^2e^t

\int t^{2} e^{t} d t

t^{2} e^{t} - 2 (e^{t} t - e^{t}) + C

Solution steps

\int t^{2} e^{t} d t

Apply Integration By Parts

: t^{2} e^{t} - \int 2 t e^{t} d t

= t^{2} e^{t} - \int 2 t e^{t} d t

\int 2 t e^{t} d t = 2 (e^{t} t - e^{t})

= t^{2} e^{t} - 2 (e^{t} t - e^{t})

Add a constant to the solution

= t^{2} e^{t} - 2 (e^{t} t - e^{t}) + C

n = 1 \sum \infty \frac{n - 1}{n}

\int 12 x^{2} + 6 x - 4 d x

\frac{\partial}{\partial x} (y cos (x y) - y sin (x y))

h \to 0 lim (\frac{( sin ( \frac{π}{6} + h ) - \frac{1}{2} )}{h})

(t + 4)^{\frac{2}{3}} (3 t^{2} - 2)^{3}